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1、衡水金卷先享题 2026年高三一轮复习夯基卷 地理W(一)1试题


3、衡水金卷先享题 2026年高三一轮复习夯基卷 化学W(一)1试题


C. The marked advantage of small local businesses over large ones.
D. The crucial role of joint efforts in conserving cultural treasure.
C
This week, Google researchers published a paper describing results from an AI tool built to create music. The tool, called MusicLM, is not the first AI music tool to be launched. But the examples Google provided demonstrate musical creative ability based on a limited set of descriptive words.
Several different music examples produced by MusicLM were published online. Some of the generated music came from just one or twoword descriptions, such as "jazz", "rock" or "techno". The tool also created other examples from more detailed descriptions containing whole sentences.
In one example, Google researchers included these instructions to MusicLM, "It is a soundtrack of a game. It is fastpaced and upbeat, with a catchy electric guitar riff. The music is repetitive and easy to remember, but with unexpected sounds ..." In the resulting recording, the music seemed to keep very close to the description. The team said the more detailed the description was, the better the system could attempt to produce it.
The MusicLM model operates similarly to the machinelearning systems used by ChatGPT. ChatGPT and MusicLM both require powerful computers to operate complex machinelearning models. The San Franciscobased company OpenAI launched ChatGPT late last year. ChatGPT has recently received a lot of attention because of its ability to generate complex writings and other content from just a simple description in natural languages. Such tools can produce humanlike results because they are trained on huge amounts of data. Many different materials are fed into the systems to permit them to learn complex skills to create realistic works.


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1、衡水金卷先享题 2026年高三一轮复习夯基卷 数学W(一)1答案


3、衡水金卷先享题 2026年高三一轮复习夯基卷 语文W(一)1答案


3、衡水金卷先享题 2026年高三一轮复习夯基卷 化学W(一)1答案


1、衡水金卷先享题 2026年高三一轮复习夯基卷 政治W(一)1答案


1、衡水金卷先享题 2026年高三一轮复习夯基卷 生物W(一)1试题


1、衡水金卷先享题 2026年高三一轮复习夯基卷 语文W(一)1答案


(3)谁弱谁水解——发生水解的是弱碱阳离子或弱酸阴离子。
(4)谁强显谁性——组成盐的酸根离子(碱的阳离子)是强酸根离子(强碱的阳离子)，则显酸(碱)性。
(5)都弱都水解——弱酸弱碱盐因阴、阳离子都能发生水解且两水解过程可相互促进，所以水解程度较大，少数可以完全水解。
(6)同强显中性——①强酸强碱盐溶液显中性；②盐中的阳离子对应的碱的电离常数Kb与盐中的阴离子对应的酸的电离常数Ka相等时，盐溶液呈中性，如CH3COONH4溶液呈中性。
(7)越弱越水解——组成盐的酸根离子对应的酸(即水解生成的酸)酸性越弱(或阳离子对应的碱的碱性越弱)，水解程度就越大，此即“越弱越水解”规律。
电离程度：CH3COOH＞H2CO3＞HCN＞HCO，水解程度：CH3COO－＜HCO＜CN－＜CO。
4．盐类水解反应离子方程式的书写


1.下列有关物质用途的说法错误的是()
A.该反应为置换反应，置换反应一定是氧化还原反应
A.将空气充人食品包装袋用作防腐剂
B.用激光笔照射硫酸铜溶液，溶液中有一条光亮的通路
B.电解水时用硫酸钠增加溶液的导电性
C.“外化而内不化”时得到的金属能导电为电解质
C.二氧化碳制成干冰用于人工降雨


3、衡水金卷先享题 2026年高三一轮复习夯基卷 生物W(一)1答案