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1、[百师联盟]2026届高三仿真模拟考试(五)5地理(百)试题


6、[百师联盟]2026届高三仿真模拟考试(五)5生物(百)试题


十、第三节（共5小题；每小题2分，满分10分）
（2025七下·东坡期末）阅读下面短文，根据其内容，补全表格中所缺信息。请将答案按编号依次填入表格内题号后横线上。每空限填一词。
Do you know what a healthy meal is To help the people know this, the US makes a new food diagram called MyPlate. Parents can use it to develop healthy eating habits for their children and the whole family.
MyPlate is a picture of a plate showing how much food you should eat every meal. The food are fruits, vegetables, grains (谷物), protein (蛋白质), and dairy. Fruit includes any fruit or 100 percent fruit juice. Your fruit can be fresh, frozen, canned, dried, or whole, cut. The goal is to provide your child with vital nutrients (营养成分). Choose veggies that are colorful, such as red peppers, dark green spinach, or yellow squash. Protein food includes both animal (meat, poultry, seafood and eggs) and plant sources (beans, peas, soy products, nuts and seeds). Grains include any food made from wheat, rice, or other cereal grain.
The picture helps people eat well. And it is an easy way for us to know how to eat well. Look at the plate, we can see that fruits and vegetables should make up half of a meal. It also means that fruits and vegetables should make up about half of what we eat each day. Smaller parts are grains, protein, and dairy. If we eat like this we can keep healthy.
　 helps us have a healthy eating　56． 　 .
shows us how much we should eat every　57． 　 .


2. Which of the following is NOT the benefit of the Mobile Gym
A. It saves much of clients ’time.
B. It creates adequate private space.
C. It offers special equipment needed for a total-body workout.
D. It provides clients with an appropriate and effective workout.
3. What’s Zickerman’s attitude towards the Mobile Gym
A. Concerned. 　　　 B. Negative.


6、[百师联盟]2026届高三仿真模拟 (五)5地理(百)答案


2、[百师联盟]2026届高三仿真模拟考试(五)5生物学(百)答案


5、[百师联盟]2026届高三仿真模拟考试(五)5英语(百)答案


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6、[百师联盟]2026届高三仿真模拟考试(五)5地理(百)答案


2．在常温下，改变下列条件，分析条件的改变对水的电离平衡H2OH＋＋OH－的影响，填写下表：
改变条件 电离平衡 移动方向 溶液中 c(H＋) 溶液中 c(OH－) pH 溶液的 酸碱性 Kw
升高温度 正向 增大 增大 <7 中性 增大
加入酸 逆向 增大 减小 <7 酸性 不变
加入碱 逆向 减小 增大 >7 碱性 不变
加入活泼金属(如Na) 正向 减小 增大 >7 碱性 不变
加入CH3COONa(s) 正向 减小 增大 >7 碱性 不变


【详解】A．步骤Ⅰ中产生的蓝色沉淀是Cu(OH)2，而非[Cu(NH3)4]SO4。因为适量浓氨水与CuSO4溶液反应首先生成Cu(OH)2沉淀，过量氨水才会溶解沉淀形成络合物，A错误；
B．步骤Ⅱ中，深蓝色溶液（加入浓氨水）中的Cu2+因形成[Cu(NH3)4]2+络离子而浓度降低，而蓝色溶液（加入稀盐酸）中Cu2+可以自由移动，浓度较高。因此c深蓝色(Cu2+) < c蓝色(Cu2+)，B正确；
C．步骤Ⅲ中无明显现象并非因铁钉钝化。铁在碱性溶液中不易钝化，且后续加入盐酸后有反应发生，说明铁未钝化。真正原因是络合物中Cu2+浓度过低，无法被Fe置换，C错误；
D．步骤Ⅲ中加入盐酸后，H+与NH3结合生成NH4+，导致配合物释放Cu2+，随后Fe与H+反应生成H2（气泡），并与Cu2+发生置换反应生成Cu，D的反应式未体现H+的作用，与实际反应原理不符，D错误；
故选B。
15．C
【详解】A．恒压条件下通入N2，容器体积增大，NO2和N2O4的浓度均降低，平衡向NO2增加颜色的方向移动，A错误；


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