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试题答案

本文从以下几个角度介绍。

    1、2024年重庆一中高考数学三诊试卷
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    8、重庆一中高2024级高三上期第二次月考数学答案
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6、重庆一中2025年高三高考适应性考试·最后一卷数学试题


3、重庆一中2025年高三高考适应性考试·最后一卷数学试题


A: That's great. We just need a person like you.5. _______
B: My name is Tom Green.
A: OK. Welcome to join us.
B: Thank you!
【中考模拟】
Ⅵ.单项选择。
（　　）1.（淮安中考）--Amy,do you know Lang Lang and his wife


Every spring, there are sports meets at many middle schools. When students on the playground get together and shout loudly, “One, two, one, two." Do you know what game it is It is tug-of-war.
Tug-of-war is a team sport between two teams at each end of a rope (绳). It first came into being in China 2,400 years ago. It is very popular in China and many other countries. But in other countries, their tug-of-war match is a little different from ours. They have eight men for each team , while we may have the match between two sides with the equal number of men or women players. For example, we may have 10 men players and 10 women players on each team. Of course, they are usually tall, strong and heavy.
For a tug-of-war match , we need a long thick (厚的) rope. Each team stands at one end of the rope, holding it. There's a white line in the middle of the field. Then they try to pull (拉) the centre of the rope to each of their own sides. The winning team is the one that pulls the other over the line.
Tug-of-war was once an Olympic sporting event. It lasted until 1920. Though it isn't an Olympic sport now, people in many countries still like playing it very much.
( )26.Which of the following is the game of “ tug-of-war"
B. C. D.
( )27.What does the underlined word “equal” in Paragraph 2 mean


5、重庆一中2025年高三高考适应性 ·最后一卷数学试题


4、重庆一中2025年高三高考适应性考试·最后一卷数学试题


5、重庆一中2025年高三高考适应性考试·最后一卷数学试题


1、重庆一中2025年高三高考适应性考试·最后一卷数学试题


6、重庆一中2025年高三高考适应性考试·最后一卷数学试题


5、重庆一中2025年高三高考适应性考试·最后一卷数学试题


【进行实验】
（3）同学们猜想步骤③产生的气体可能是二氧化碳，经讨论设计如图方案进行探究。
实验方案 实验现象 实验结论
　 　 产生的气体是二氧化碳
【拓展探究】
（4）二氧化碳可与水反应产生碳酸，写出反应原理　 　（用化学方程式表示），因此自制汽水也称为碳酸饮料。为证明二氧化碳能与水反应，同学们经讨论设计如图方案进行探究。
实验方案 实验现象 实验结论


A.酸雨形成的原因：CO2+HO=HCO3
B.用稀硫酸除铁锈：Fe2O3+3H2S04=2FeS04+3Hz0
C.一氧化碳还原氧化铁：4C0+Fe304高温3Fe+4C02
D.用氢氧化镁治疗胃酸过多症：2HC1+Mg(OHD2=MgCl2+2HO
14.一定质量的甲烷在02不足的情况下燃烧，生成C02、C0和水，其中生成水的质量是10.8g
则生成C0和C02总质量可能是()
A.16.8g


3、重庆一中2025年高三高考适应性考试·最后一卷数学答案