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试题答案

本文从以下几个角度介绍。

    1、绥德一中2024年高考
    2、绥德一中2024年高考喜报
    3、2024绥德一中喜报
    4、绥德中学2024年高考
    5、绥德一中官网
    6、绥德一中发声
    7、绥德一中喜报
    8、绥德一中全名
    9、绥德一中吧
    10、绥德一中成绩查询

5、绥德一中高2026届摸底考试(10月)政治试题


3、绥德一中高2026届摸底考试(10月)生物试题


—_________
21. —_________
—It’s OK, Chen Jie. _________
22. —Hey, Sarah! I can help you.
—_________
2025-2026度第一学期
三年级英语素养评价 (一)


D. Those interested in improving social skills.
3. Which virtue does Secrets We Keep stress
A. Honesty. B. Team spirit. C. Social responsibility. D. Courage.
B
Known lovingly as “Dr. Tree”, Jim Chi-yung, an expert of Geography and Environmental Science at the Education University of Hong Kong, stands out as a champion of Hong Kong’s green heritage (遗产). His pioneering work in forestry has helped change the city’s skyline into a greener, more sustainable (可持续的) space, offering models for other cities struggling for environmental challenges.
In September this year, a ranking by Standford University named Jim the world’s leading forestry scientist, out of more than 35,000 researchers, who has spent the past forty-plus years protecting and creating many natural areas in the most unexpected places.
Jim’s efforts are particularly obvious in his protection of “champion trees” — ancient species that form the backbone of Hong Kong’s green heritage. Many of these trees, such as the centuryold camphor trees on Haiphong Road, were threatened during the city’s growth and storms, Fortunately, Jim came to their rescue with his knowledge. “Champion trees are important to Hong Kong’s natural and cultural identity, and cannot be left unattended,” Jim says. His efforts also led to the creation of a government list for ancient trees. For more than ten years, Jim has been taking the lead in shaping government plans that protect these natural historical sites.


3、绥德一中高2026届摸底 (10月)生物学答案


5、绥德一中高2026届摸底考试(10月)生物学答案


6、绥德一中高2026届摸底考试(10月)地理答案


1、绥德一中高2026届摸底考试(10月)化学答案


5、绥德一中高2026届摸底考试(10月)生物学试题


3、绥德一中高2026届摸底考试(10月) 答案


【解析】(1)NaHCO3不稳定,受热易发生分解生成Na2CO3、CO2和H2O。(2)②Na2CO3溶于水放出热量,温度升高;Na2CO3溶液显碱性,滴加酚酞后溶液显红色。(3)①Na2CO3与盐酸的反应分步进行,先转化为NaHCO3,NaHCO3 再与盐酸反应生成CO2,故NaHCO3与盐酸反应更剧烈;②由题意可知,n(HCl)=0.003 L×1 mol·L-1=0.003 mol,完全反应消耗Na2CO3和NaHCO3的质量分别为0.003 mol××106 g·mol-1=0.159 g、0.003 mol×84 g·mol-1=0.252 g,因此在反应中盐酸均不足,计算生成气体的体积要依据盐酸的量且装置Ⅰ中产生H2较多。(4)操作1中的白色沉淀是碳酸钙,这说明碳酸钠能和氯化钙反应生成碳酸钙白色沉淀,反应的离子方程式为Ca2++CCaCO3↓;操作2的实际现象为产生白色沉淀和气体,这说明白色沉淀是CaCO3,气体是CO2,因此在该条件下,NaHCO3溶液与CaCl2溶液反应的离子方程式为Ca2++2HCCaCO3↓+CO2↑+H2O。

√
[解析] 根据离子方程式中电荷守恒可知，右边正负电荷中和，左边
，，A错误；
中元素从价降到 价，则 为氧化剂，发生还原反应，
B错误；
随着反应的进行，反应生成的增多，溶液酸性增强，C错误；
氧化剂是， 是还原剂，是还原产物，还原剂与还原产


3、绥德一中高2026届摸底考试(10月)化学答案